Initialize an array of size 10 and find the largest integer and smallest integer in the array. Also to display the array elements 5 per line then display in the new line the largest and smallest integer.

class array8

{

public static void main(String as[])

{

int arr[]={10,5,25,3,-4,100,1000,-10,77,38};

System.out.println("array numbers line no.1");

for(int i=0;i<=4;i++)

System.out.print(arr[i]+" ,");

System.out.println("\narray numbers line no.2");

for(int i=5;i<arr.length;i++)

System.out.print(arr[i]+" ,");

int max,min;

int i;

max=arr[0];

for(i=0;i<arr.length;i++)

{

if(arr[i]>max)

max=arr[i];

}

min=arr[0];

for(i=0;i<arr.length;i++)

{

if(arr[i]<min)

min=arr[i];

}

System.out.println("\nlargest no:"+max);

System.out.println("smallest no:"+min);

}

}

output:

D:\JavaPrograms\ArrayPrograms>javac array8.java

D:\JavaPrograms\ArrayPrograms>java array8
array numbers line no.1
10 ,5 ,25 ,3 ,-4 ,
array numbers line no.2
100 ,1000 ,-10 ,77 ,38 ,
largest no:1000
smallest no:-10